Topological Sort / Cycle Detection. Before going into them, whenever you are dealing with representing graphs in files, you have to decide how you are going to format them. If there is a cycle, I assume the topological order is useless. I was trying to write code for detecting a cycle in a directed graph and if there is no cycle then return a topological order of the same. If the given graph contains a cycle, then there is at least one node which is a parent as well as a child so this will break Topological Order. The answer is that both approaches will work. graph can contain many topological sorts. The idea is to simply use Kahn’s algorithm for Topological Sorting. We have discussed a DFS based solution to detect cycle in a directed graph.In this post, BFS based solution is discussed. If there are no cycles, I assume the topological order I found is valid. Minimum time taken by each job to be completed given by a Directed Acyclic Graph Hard Given a Directed Acyclic Graph having V vertices and E edges, where each edge {U, V} represents the Jobs U … The topological sort may not be unique i.e. So, initially all vertices are white. Am I correct so far? Use the following approach: consider we have three colors, and each vertex should be painted with one of these colors. And the answer is: If no vertex has indegree 0, we can find a cycle by tracing backwards through vertices with positive indegree; since every vertex on the trace back has a positive indegree, we eventually reach a vertex twice, and the cycle has been found. And if the graph contains cycle then it does not form a topological sort, because no node of the cycle can appear before the other nodes of the cycle in the ordering. While I was searching for it I came across different techniques like DFS and topological sorting to detect cycle in a directed graph. Your function should return true if the given graph contains at least one cycle, else return false. "Black" means we've visited all vertices in subtree and left the vertex. Steps involved in detecting cycle in a directed graph using BFS. I can determine the topological sort of a directed graph using DFS algorithm. My union find code only get 38/47 test cases passed. Thus, the above file defines a directed graph. "White color" means that the vertex hasn't been visited yet. Is "topological sort of an undirected graph… Topological Sort: TS can be only used to directed graph. Detect Cycle in a Directed Graph Given a directed graph, check whether the graph contains a cycle or not. Please corect me if this is not true. Detect cycle in Directed Graph using Topological Sort , In Topological Sort, the idea is to visit the parent node followed by the child node. (Don’t use depth first search, we want just a modification of the basic topological sort.) What about undirected graphs? Union Find: For this question, since a child can have multiple parents, things get tricky. Here's a little code for topological sort and cycle detection. Detect cycle in a directed graph using topological sort. It seems like your question is the following: can you use depth-first search to detect cycles in an undirected graph, or should you use topological sort instead? An acyclic graph always has a topological sort. "Gray" means that we've visited the vertex but haven't visited all vertices in its subtree. If there is a cycle in a directed graph, then you can detect this by running a depth-first search over the graph. Multiple parents, things get tricky cycle in a directed graph 38/47 test cases passed check whether graph... Subtree and left the vertex has n't been visited yet DFS and topological Sorting use Kahn ’ s for... A directed graph, check detect cycle in a directed graph using topological sort the graph of these colors means we visited... 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